X^2+96x=13,68

Solution for X^2+96x=13,68 equation:

X^2+96X=13.68

We move all terms to the left:

X^2+96X-(13.68)=0

We add all the numbers together, and all the variables

X^2+96X-13.68=0

a = 1; b = 96; c = -13.68;
Δ = b2-4ac
Δ = 962-4·1·(-13.68)
Δ = 9270.72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-\sqrt{9270.72}}{2*1}=\frac{-96-\sqrt{9270.72}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+\sqrt{9270.72}}{2*1}=\frac{-96+\sqrt{9270.72}}{2}
$